![]() The results can then be plotted and the maximum shear and moment can be easily identified. The shear and moment may not be continuous across a load or support.Įach section needs to be cut and analyzed for shear and moment as a function of x from the left edge. Since the beam has forces acting at four locations, the shear and moment needs to be analyzed in four different sections. (Reaction forces can also be calculated by dividing sum of forces acting on the beam by 2, since the beam and loading are symmetrical.) Since there is no horizontal applied load, A x will be zero. Taking moments about support A and assuming counter clockwise (CCW) moment as positive gives, The unknown reactions can be found by applying the three standard equilibrium equations. To calculate them, the distributed load is converted into an equivalent point load of (3 kN/m) (3 m) = 9 kN which is located 3 m from support A as shown in the diagram. There will be three possible reactions at A and B namely A x, A y and B y. Draw the shear and moment diagram for the beam shown in figure.īefore the shear and moment can be determined at any internal location, the boundary conditions need to be calculated.
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